A naturally occurring substance has the const | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The molecule has $4$ chiral centers (marked with $*$ in the structure). It also has $2$ double bonds $(C=C)$ that can exhibit geometrical isomeris

Vedclass · Accepted Answer

$64$

Vedclass · Answer

(D) The molecule has $4$ chiral centers (marked with $*$ in the structure). It also has $2$ double bonds $(C=C)$ that can exhibit geometrical isomerism $(G.I.)$. Since the molecule is unsymmetrical,the total number of stereoisomers is given by $2^n$,where $n$ is the sum of chiral centers and double bonds capable of $G.I.$. Here,$n = 4 + 2 = 6$. Therefore,total stereoisomers $= 2^6 = 64$.

$A$ naturally occurring substance has the constitution shown below. How many stereoisomers may have this constitution?

Similar Questions

Most stable carbocation among the following is

The correct decreasing order in the enol content of the following molecules is:

The possible number of stereoisomers of the product of the following reaction would be: $Ph - CH = CH - CH(CH_3) - CHO \xrightarrow[pH = 4.5]{H_2N - OH}$ ?

The number of stereoisomers formed by the given compound is

The method of preparing an optically active substance from a symmetric molecule in the presence of an optically active substance is called .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module